This is an online educational tools to make graph of mathematical polar functions of 2D. Type any function of variable r in the first input box and any function of t in the second input box, then press the drawing button. It takes sometimes to draw graph of this function and be patience to calculate huge points to draw the graph..For zoom this graph, you can change zoom value of the zoom input box. You can see the user manual for properly use the online tools. Thank you for viewing this article.
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Polar coordinate system is a two-dimensional coordinate system in which each point on a plane is determined by a distance from a fixed point and an angle from a fixed straight line. If the distance from fixed pont is r and the angle from the fixed line is θ ,then the coordinate will be (r, θ). For learn about Math functions of Mathematics and graphing, visit: Graphing Math functions of Math.
Free online graphing calculator for math for graph drawing website www.graph2d.com can draw any polar function. You can type 10cos(4t) for Polar rose in the input box and then press drawing button to get the graph. For learn about Piecewise function of Mathematics and graphing, visit: Graphing Piecewise function of Math.
Free online graphing calculator for math for graph drawing website www.graph2d.com can draw any polar function. You can type 2/(1+.75cos(t)) for Polar ellipse in the input box and then press drawing button to get the graph. For learn about Complex Analysis of Mathematics and graphing, visit: Graphing Complex Analysis of Math.
Cardioid is a heart shaped curve which mathematics polar equations are r = a(1 ± cosθ) and r = a(1 ± sinθ) .The Cardioid word come from Greek word, which means “heart”. It is used higher Mathematics specially integral calculus. As for example, r = 8(1 +sinθ) . For drawing by free graphing calculator, type right input box 10(1+sin(t)), then press drawing button and you can get this graph of polar Cardioid or heart shaped curve.
As for another example, r = 10(1 -cosθ) . For drawing by free graphing calculator, type right input box 8(1-cos(t)), then press drawing button and you can get this graph of polar Cardioid or heart shaped curve. For learn about Linear programming or operation research of Mathematics and graphing, visit: Graphing Operation research of Math.
The limacon is a closed curve like circle whose polar equations are r=a±bcosθ and r=a±bsinθ where a and b are not zero. As for example, r = 8+6sinθ . For drawing by free graphing calculator, type right input box 8+6sin(t), then press drawing button and you can get this graph of polar limacon curve. For learn about Polar function of Mathematics and graphing, visit: Graphing polar function of Math.
The looped limacon is a closed curve with a loop whose polar equations are r=a±bcosθ and r=a±bsinθ where a and b are not zero and b>a . As for example, r = 8+6sinθ . For drawing by free graphing calculator, type right input box 5+7sin(t), then press drawing button and you can get this graph of polar looped limacon curve. For learn about Parametric functions of Mathematics and graphing, visit: Graphing Parametric functions of Math.
The archimedean spiral polar equation is a closed curve whose polar equations are r=a+bθ. As for example, r = 4+2θ . For drawing by free graphing calculator, type right input box 3+2t, then press drawing button and you can get this graph of The archimedean spiral polar graph . For learn about Implicit functions of Mathematics and graphing, visit: Graphing Implicit function of Math.
How to convert cartesian equation to polar equation
For convert cartesian equation to polar equation , substituting x=rcosθ and y=rsinθ in the cartesian equation and then simplify the equation and you get the polar equation . As for example, x2+y2-5x-6y=0 is a cartesian equation, putting x=rcosθ and y=rsinθ in the cartesian equation, then we get (rcosθ)2+(rsinθ)2-5rcosθ-6rsinθ=0 =>r2{cos2θ+sin2θ}=r(5cosθ+6sinθ)=>r=5cosθ+6sinθ
The equation of a rose is r=3sin(2θ). When r=0, then we can get θ=0 or θ=Π/2. This can be seen by solving the equation 3sin(2θ)=0 for θ. Therefore the values θ=0 to θ=π/2 trace out the first petal of the rose . To find the area inside this petal,use Equation r=3sin(2θ). So Area of one petal is A=(1/2)∫0π/2 r2dθ=(1/2)∫0π/2 {3sin(2θ)}2dθ=9π/8 Square units. If we want to get the total area of four petals, then we multiply 4 with the area of one petal of the rose . hence the total area =4X9π/8=9π/2 square units. .
